7y^2-10y+3=(7y-3)

Solution for 7y^2-10y+3=(7y-3) equation:

7y^2-10y+3=(7y-3)

We move all terms to the left:

7y^2-10y+3-((7y-3))=0


We calculate terms in parentheses: -((7y-3)), so:

(7y-3)

We get rid of parentheses

7y-3

Back to the equation:

-(7y-3)


We get rid of parentheses

7y^2-10y-7y+3+3=0

We add all the numbers together, and all the variables

7y^2-17y+6=0

a = 7; b = -17; c = +6;
Δ = b2-4ac
Δ = -172-4·7·6
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-11}{2*7}=\frac{6}{14}
=3/7
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+11}{2*7}=\frac{28}{14}
=2
$